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Replies:
2
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Pages:
1
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Last Post:
Mar 8, 2012 2:10 PM
by: Erlanger
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Posts:
9
Registered:
3/8/12
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Queue with no binding gets all the messages?
Posted:
Mar 8, 2012 1:40 PM
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This is a question regarding the example in Listing 3.1 in the latest version of the book (downloaded March 7 2012)
There are three queues declared, two queues bound to routing keys, as show in the following code example from the book.
$channel->queue_declare('msg-inbox-errors',
false, true, false, false);
$channel->queue_declare('msg-inbox-logs',
false, true, false, false);
$channel->queue_declare('all-logs', false,
true, false, false);
$channel->queue_bind('msg-inbox-errors',
'logs-exchange', 'error.msg-inbox');
$channel->queue_bind('msg-inbox-logs',
'logs-exchange', '*.msg-inbox');
THE QUESTION IS: why the "all-logs" queues are getting all message as indicated in the listing result even though that queue has no binding rule declared?
Listing queues ...
msg-inbox-logs 0
msg-inbox-errors 0
all-logs 3
...done.
Than you.
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Posts:
13
From:
Shanghai
Registered:
11/21/10
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Re: Queue with no binding gets all the messages?
Posted:
Mar 8, 2012 1:46 PM
in response to:
Erlanger
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Hi,
This seems a bit confusing but the idea of the script is just to explore the queues and bindings using the rabbitmqctl command.
Also a queue with no bindings can get messages if you publish them to the anonymous exchange using the queue name as routing key.
So the 3 there is just as an example.
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Posts:
9
Registered:
3/8/12
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Re: Queue with no binding gets all the messages?
Posted:
Mar 8, 2012 2:10 PM
in response to:
alvaro.videla
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Thank you for your reply.
As I read along, I got your point that each queue is bound to the anonymous exchange using the queue name as the routing key.
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